How many stereoisomers can be drawn for the following molecule?
$H_{3} {CCH}_{2} CH = {CHCH}_{2} CH (Cl) {CH}_{3}$

Question

How many stereoisomers can be drawn for the following molecule? H_3CCH_2CH=CHCH_2CH(Cl)CH_3

MARKS Content Team · Accepted Answer

Correct answer: 4. There are two stereo centrers. So, number of stereoisomers = 2^n = 2^2 =4

Solution