Q151 / 270 · NDA 2022 (Phase 2) · Mathematics
How many four-digit natural numbers are there such that all of the digits are odd?
- Correct answerA$625$
- B$400$
- C$196$
- D$120$
Solution
Odd digits $=1,3,5,7,9$

Number of four digits number with all odd digits $=5 \times 5 \times 5 \times 5=625$

Number of four digits number with all odd digits $=5 \times 5 \times 5 \times 5=625$
Hence, the correct answer is option: 'A'.