$\mathrm{CH}_{3}-\mathrm{CN} \stackrel{\mathrm{Na}_{2} \mathrm{C}_{5} \mathrm{OH}}{\longrightarrow} A \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} B \underset{573 \mathrm{~K}}{\stackrel{\mathrm{Cu}}{\longrightarrow}} C$ here $C$ is

• A

  $\mathrm{CH}_{3}-\mathrm{CH}_{2} \mathrm{NHOH}$
• Correct answer
  B

  $\mathrm{CH}_{3}-\mathrm{CHO}$
• C

  $\mathrm{CH}_{3} \mathrm{CO}-\mathrm{NH}_{2}$
• D

  $\mathrm{CH}_{3}-\mathrm{COOH}$

Solution

The complete reaction takes place as follows :

Hence, the correct answer is option: 'B'.