Q36 / 125 · BITSAT 2020 · Chemistry
$\mathrm{n}\left(\mathrm{CF}_{2}=\mathrm{CF}_{2}\right) \frac{\text { Benzoyl peroxide or }}{\left(\mathrm{NH}_{4}\right)_{2} \mathrm{~S}_{2} \mathrm{O}_{8}} \mathrm{X}$
Here, $\mathrm{X}$ is:
- ARMMA
- B$\mathrm{PVC}$
- C$\mathrm{PAN}$
- Correct answerDNone of these
Solution

Here $X$ is polytetrafluoroethylene. So, none of these i.e., option (d) is correct choice.
Hence, the correct answer is option: 'D'.