Q3 / 150 · MHT CET 2021 (20 Sep Shift 1) · Chemistry

Henry's law constant for $\mathrm{CH}_3 \mathrm{Br}$ is $0.16 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}$ at $298 \mathrm{~K}$. What pressure is required to have solubility of $0.08 \mathrm{~mol} \mathrm{~L}^{-1}$ ?

  • A
    $0.24 \mathrm{bar}$
  • B
    $1.6 \mathrm{bar}$
  • Correct answer
    C
    $0.5 \mathrm{bar}$
  • D
    $4.0 \mathrm{bar}$

Solution

According to Henry's Law Solubility of gas $=\mathrm{K}_{\mathrm{H}}$. $\mathrm{P}_{\text {gas }}$ $$ \begin{aligned} & \mathrm{P}_{\text {gas }}=\text { Solubility } / \mathrm{K}_{\mathrm{H}} \\ & =\frac{0.08}{0.16} \\ & =0.5 \mathrm{bar} \end{aligned} $$

Hence, the correct answer is option: 'C'.

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