Q100 / 180 · AIIMS 2012 · Physics

Half life of a radio-active element is 8 years, how much amount will be present after 32 years?

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{8}$
  • Correct answer
    C
    $\frac{1}{16}$
  • D
    $\frac{1}{32}$

Solution

Here, $T_{1 / 2}=8$ years $t=32$ years Using, $N=N_0\left(\frac{1}{2}\right)^{\frac{t}{T_{1 / 2}}}$ $\left(\frac{\mho_0}{\mho_0}\right)=\left(\frac{1}{2}\right)^{\frac{32}{8}}=\left(\frac{1}{2}\right)^4$ $\left(\frac{\approx}{\nabla_0}\right)=\frac{1}{16}$

Hence, the correct answer is option: 'C'.

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