H₂O₂ can not be synthesized by

• A

  Addition of ice cold H₂SO₄ on BaO₂
• Correct answer
  B

  Addition of ice cold H₂SO₄ and PbO₂
• C

  Aerial oxidation of 2 ethyl anthraquinol
• D

  Electrolysis of (NH₄)₂SO₄ at a high current density

Solution

${\text{(i) BaO}}_{\text{2}}\text{(s)}\text{+}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\text{(aq)}\to {\text{BaSO}}_{\text{4}}\text{(s)}\downarrow \text{+}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}\text{(aq)}$
${\text{(ii) PbO}}_{\text{2}}\text{+}{\text{2H}}_{\text{2}}{\text{SO}}_{\text{4}}\to {\text{Pb(SO}}_{\text{4}}\text{)}\text{+}{\text{2H}}_{\text{2}}\text{O}$
${\text{PbO}}_{\text{2}}\text{+}{\text{2H}}_{\text{2}}{\text{SO}}_{\text{4}}\stackrel{\Delta }{\to }{\text{2PbSO}}_{\text{4}}\text{+}{\text{O}}_{\text{2}}\text{+}{\text{2H}}_{\text{2}}\text{O}$

$\to$ Electrolysis of $\to {{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{ SO}}_{\text{4}}$
(at cathode:- ${\text{H}}^{\text{+}}$ and ${\text{NH}}_{\text{4}}^{\text{+}}$ ions attracted
$\to {\text{NH}}_{\text{4}}^{\text{+}}\to {\text{NH}}_{\text{3}\left(\text{g}\right)}\text{+}\stackrel{\oplus }{\text{H}}$
${\text{2H}}^{\text{+}}\text{+}{\text{2e}}^{-}\to {\text{H}}_{\text{2}}$)
(at anode ${\text{OH}}^{-}\text{+}{\text{SO}}_{\text{4}}^{-\text{2}}$ ions attracted
${\text{4OH}}^{-}\to {\text{O}}_{\text{2}}\text{+}{\text{H}}_{\text{2}}{\text{O}}_{\text{2}}\text{+}{\text{4e}}^{-}$)

Hence, the correct answer is option: 'B'.