Q93 / 125 · BITSAT 2021 · Physics
Green light of wavelength $5460 Å$ is incident on an airglass interface. If the refractive index of glass is $1.5$, the wavelength of light in glass would be $\left(\mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1}\right)$
- Correct answerA$3640 Å$
- B$5460 Å$
- C$4861 Å$
- DNone of the above
Solution
$\mathrm{a}^{\lambda} \mathrm{g}=\frac{\lambda_{\mathrm{a}}}{\mu}=\frac{5460}{1.5}=3640 Å$
Hence, the correct answer is option: 'A'.