Glucose gives silver mirror with ammoniacal silver nitrate because it has

• Correct answer
  A

  aldehyde group
• B

  ester group
• C

  ketone group
• D

  alcoholic silver nitrate

Solution

Glucose gives silver mirror with ammoniacal silver nitrate because of presence of $-$ CHO group (aldehyde group) in the structure of glucose. $$ \mathrm{CH}_{2} \mathrm{OH}(\mathrm{CHOH})_{4} \mathrm{CHO}+\mathrm{Ag}_{2} \mathrm{O} $$

Hence, the correct answer is option: 'A'.