Q1 / 160 · TS EAMCET 2020 (14 Sep Shift 2) · Chemistry

Given the ratio of kinetic energy of electron in two orbitals is $16: 9$. Calculate the ratio of wavelength of electron waves?

  • A
    4 : 3
  • B
    9 : 16
  • Correct answer
    C
    3 : 4
  • D
    16 : 9

Solution

From de-Broglie's equation, $\lambda=\frac{h}{m v}=\frac{h}{\sqrt{2 m \times \mathrm{KE}}}$ $\Rightarrow$ For an electrons, $\lambda \propto \frac{1}{\sqrt{\mathrm{KE}}} \Rightarrow \frac{\lambda_{16}}{\lambda_9}=\sqrt{\frac{9}{16}}=3: 4$

Hence, the correct answer is option: 'C'.

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