Q13 / 90 · JEE Main 2023 (11 Apr Shift 1) · Chemistry

Given below are two statements :

Statement-I : Methane and steam passed over a heated Ni catalyst produces hydrogen gas.

Statement-II : Sodium nitrite reacts with NH4Cl to give H2O, N2 and   NaCl.

In the light of the above statements, choose the most appropriate answer from the options given below :

  • A
    Statement I is incorrect but Statement II is correct
  • B
    Both the statements I and II are incorrect
  • C
    Statement I is correct but Statement II is incorrect
  • Correct answer
    D
    Both the statements I and II are correct

Solution

In steam-methane reforming, methane reacts with steam under  3–25 bar pressure in the presence of a nickel catalyst to produce hydrogen, carbon monoxide, and a relatively small amount of carbon dioxide. Steam reforming is endothermic, that is, heat must be supplied to the process for the reaction to proceed.

NaNO2+NH4Cl→∆N2+NaCl+H2O

as NH4NO2→∆N2+H2O

Hence, both the statements are correct.

Hence, the correct answer is option: 'D'.

Relevant Questions