Q131 / 160 · WBJEE 2011 · Physics
Given \(\overrightarrow{\mathrm{A}}=2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}\) and \(\overrightarrow{\mathrm{B}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}\). The component of vector \(\overrightarrow{\mathrm{A}}\) along vector \(\overrightarrow{\mathrm{B}}\) is
- A\(\frac{1}{\sqrt{2}}\)
- B\(\frac{3}{\sqrt{2}}\)
- Correct answerC\(\frac{5}{\sqrt{2}}\)
- D\(\frac{7}{\sqrt{2}}\)
Solution
Hints: Component of \(\vec{A}\) along \(\vec{B}=\vec{A} \cdot \frac{\vec{B}}{|\vec{B}|}\)
Component of \(\overrightarrow{\mathrm{A}}\) along \(\overrightarrow{\mathrm{B}}=\frac{5}{\sqrt{2}}\)
Hence, the correct answer is option: 'C'.