$\mathrm{Ge} \left(\mathrm{Z}=32\right)$ in its ground state electronic configuration has $\mathrm{x}$ completely filled orbitals with ${\mathrm{m}}_{\mathrm{l}}=0.$ The value of $\mathrm{x}$ is __________ .

Solution

So in $\mathrm{Ge} \left(\mathrm{Z}=32\right)$ in its ground state electronic configuration has $7$ completely filled orbitals with ${\mathrm{m}}_{\mathrm{l}}=0$

Hence, the correct answer is 7.