Q16 / 100 · BITSAT 2022 · Chemistry
Ge (II) compounds are powerful reducing agents whereas $\mathrm{Pb}$ (IV) compounds are strong oxidants. It can be because
- A$\mathrm{Pb}$ is more electropositive than $\mathrm{Ge}$.
- Bionisation potential of lead is less than that of Ge.
- Cionic radii of $\mathrm{Pb}^{2+}$ and $\mathrm{Pb}^{4+}$ are larger than that of $\mathrm{Ge}^{2+}$ and $\mathrm{Ge}^{4+}$
- Correct answerDmore pronounced inert pair effect in lead has.
Solution
Inert pair effect is more pronounced in heavier members like Pb.
Hence, $\mathrm{Pb}$ (IV) compounds act as strong oxidising agents and are reduced to more stable $\mathrm{Pb}$ (II) compounds.
Hence, the correct answer is option: 'D'.