From the given standard electrode potentials of two half cells
$\mathrm{F}{\mathrm{e}}^{++}+2{\mathrm{e}}^{-}\mathrm{}\to \mathrm{}\mathrm{F}\mathrm{e}\mathrm{};\mathrm{}{\mathrm{E}}^{\mathrm{o}}=-0.440\mathrm{}\mathrm{V}$
$\mathrm{F}{\mathrm{e}}^{+++}+3{\mathrm{e}}^{-}\mathrm{}\to \mathrm{}\mathrm{F}\mathrm{e}\mathrm{};\mathrm{}{\mathrm{E}}^{\mathrm{o}}=-0.036\mathrm{}\mathrm{V}$
Calculate the standard electrode potential $\left({\mathrm{E}}^{\mathrm{o}}\right)$ for
$\mathrm{F}{\mathrm{e}}^{+++}+{\mathrm{e}}^{-}\to \mathrm{}\mathrm{F}{\mathrm{e}}^{++}$ is

• Correct answer
  A

  $+0.772\mathrm{V}$
• B

  $–0.404\mathrm{V}$
• C

  $+0.404\mathrm{V}$
• D

  $–0.476\mathrm{V}$

Hence, the correct answer is option: 'A'.