Q168 / 180 · KCET 2017 · Physics

From the following graph of photo current against collector plate potential, for two different
intensities of light \( I_{1} \) and \( I_{2} \), one can conclude
Figure

  • A
    \( O I_{1}=I_{2} \)
  • B
    \( I_{1}>I_{2} \)
  • Correct answer
    C
    \( I_{1} < I_{2} \)
  • D
    Comparison is not possible.

Solution

For a fixed frequency of incident light, photo-current is directly proportional to the intensity.
Thus, from graph, photo current for light of Intensity \( I_{2} \) is more than for light of intensity \( I_{1} \), Therefore, \( I_{1} < I_{2} \)

Hence, the correct answer is option: 'C'.

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