Q115 / 125 · BITSAT 2020 · Physics
From a $200 \mathrm{~m}$ high tower, one ball is thrown upwards with speed of $10 \mathrm{~ms}^{-1}$ and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest to
- A$12 \mathrm{~s}$
- B$6 \mathrm{~s}$
- Correct answerC$2 \mathrm{~s}$
- D$1 \mathrm{~s}$
Solution
The ball thrown upward will lose velocity in ls. It return back to thrown point in another $1 \mathrm{~s}$ with the same velocity as second. Thus the difference will be $2 \mathrm{~s}$.
Hence, the correct answer is option: 'C'.