Q115 / 125 · BITSAT 2020 · Physics

From a $200 \mathrm{~m}$ high tower, one ball is thrown upwards with speed of $10 \mathrm{~ms}^{-1}$ and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest to

  • A
    $12 \mathrm{~s}$
  • B
    $6 \mathrm{~s}$
  • Correct answer
    C
    $2 \mathrm{~s}$
  • D
    $1 \mathrm{~s}$

Solution

The ball thrown upward will lose velocity in ls. It return back to thrown point in another $1 \mathrm{~s}$ with the same velocity as second. Thus the difference will be $2 \mathrm{~s}$.

Hence, the correct answer is option: 'C'.

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