Four light sources produce the following four waves : (i) $y_1=a \sin \left(\omega t+\phi_1\right)$ (ii) $y_2=a \sin 2 \omega t$ (iii) $y_3=d^{\prime} \sin \left(\omega t+\phi_2\right)$ (iv) $y_4=d^{\prime} \sin (3 \omega t+\phi)$ Superposition of which two waves give rise to interference?

• A

  (i) and (ii)
• B

  (ii) and (iii)
• Correct answer
  C

  (i) and (iii)
• D

  (iii) and (iv)

Hence, the correct answer is option: 'C'.