Q80 / 90 · JEE Main 2017 (09 Apr Online) · Physics

Four closed surfaces and corresponding charge distributions are shown below.

Let the respective electric fluxes through the surfaces be $ϕ_{1}, ϕ_{2}, ϕ_{3}$ and $ϕ_{4}$ . Then:

Solution

By Gauss law,

$ϕ = \frac{\sum q_{enclosed}}{ϵ_{o}}$

$\sum q_{enclosed}$ is same in all cases.

⇒ $ϕ$ will be same in all four cases

Hence, the correct answer is option: 'D'.