Q46 / 180 · AIIMS 2005 · Chemistry

$\mathrm{F}_2$ formed by reacting $\mathrm{K}_2 \mathrm{MnF}_6$ with

  • Correct answer
    A
    $\mathrm{SbF}_5$
  • B
    $\mathrm{MnF}_3$
  • C
    $\mathrm{KSbF}_6$
  • D
    $\mathrm{MnF}_4$.

Solution

$\mathrm{K}_2 \mathrm{MnF}_6+2 \mathrm{SbF}_5 \rightarrow 2 \mathrm{KSbF}_6+\mathrm{MnF}_3+\frac{1}{2} \mathrm{~F}_2$ In this reaction, the stronger Lewis acid $\mathrm{SbF}_5$ displaces the weaker one, $\mathrm{MnF}_4$ from its salt. $\mathrm{MnF}_4$ is unstable and readily decomposes to give $\mathrm{MnF}_3$ and fluorine.

Hence, the correct answer is option: 'A'.

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