All Exams
  1. All Exams
  2. /
  3. NEST (NISER) Paper Wise PYQs
  4. /
  5. NEST (NISER) 2012
  6. /
  7. Question
  1. All Exams
  2. /
  3. NEST (NISER) Chapter Wise PYQs
  4. /
  5. Mathematics - Sequences and Series
  6. /
  7. Question

Q36 / 55 · NEST (NISER) 2012 · Mathematics

Q19 / 20 · NEST (NISER) 2012 · Mathematics · Sequences and Series · Geometric Progression

For $x \in \mathbb{R}$ with $|x| \lt 1$, the value of $\sum_{n=0}^{\infty}(1+n) x^n$ is

  • A
    $\frac{x^2+x+1}{(1-x)^2}$.
  • B
    $\frac{1}{1-x}$.
  • C
    $\frac{x^2-x+1}{(1-x)^2}$.
  • Correct answer
    D
    $\frac{1}{(1-x)^2}$.

Hence, the correct answer is option: 'D'.

PreviousNext

More Sequences and Series Questions

  • Consider the closed interval and label it as . In the next step, divide the interval into three parts and delete the middle interval . Let b2024 (Session 1)•Geometric Progression
  • Given a prime and an integer , let denote the largest integer such that divides . Define . Then2022 (Session 1)•Geometric Progression
  • For , let Define and for . Suppose is an even number greater than or equal to 2020. Then the least value of for which is2020 (Session 1)•Geometric Progression
  • If the roots of the equation are real, positive, distinct and in geometric progression then2020 (Session 2)•Geometric Progression
  • If for some positive integer , we have , then is2017•Geometric Progression
  • Let be the sum of all integers greater than 1000 and less than 2000 . If , then is2024 (Session 2)•Arithmetic Progression

Joint Entrance Examination

  • JEE Main
  • NTA Abhyas (JEE Main)
  • JEE Advanced
  • MHTCET
  • COMEDK
  • BITSAT
  • WBJEE
  • KCET
  • AP EAMCET
  • TS EAMCET
  • VITEEE
  • Manipal (MET)
  • IAT (IISER)
  • NEST (NISER)
  • KVPY
  • NDA

Medical

  • NEET
  • AIIMS
  • JIPMER
  • NEET NTA
  • MHT-CET (PCB)

© Scoremarks Technologies Private Limited

  • Privacy policy
  • Refund & cancellation policy