For three vectors a→, b→ and c→, if |a→|=2, |b→|=1, a→×b→=c→ and b→×c→=a→, then the value of a→+b→ b→+c→ c→+a→ is equal to

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MARKS Content Team · Accepted Answer

Correct answer: 8. We know that, a→+b→ b→+c→ c→+a→=2[a→ b→ c→] Given b→×c→=a→ Taking dot product with a→, we get, a→ b→ c→=a→.a→=a→^2=4 Hence, a→+b→ b→+c→ c→+a→=2×4=8

For three vectors $\vec{a}, \vec{b}$ and $\vec{c}$ , if $| \vec{a} | = 2, | \vec{b} | = 1, \vec{a} \times \vec{b} = \vec{c}$ and $\vec{b} \times \vec{c} = \vec{a}$ , then the value of $[\vec{a} + \vec{b} \vec{b} + \vec{c} \vec{c} + \vec{a}]$ is equal to

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