For three events A, B and C of a sample space, P(exactly one of A or B occurs)= $\mathrm{P}($ exactly one of B or C occurs $)=\mathrm{P}($ exactly one of C or A occurs $)=\frac{1}{4}$. If probability of all the three events occuring simultaneously is $\frac{1}{16}$, then the probability that atleast one of the events occur is

• A

  $\frac{3}{16}$
• B

  $\frac{5}{16}$
• Correct answer
  C

  $\frac{7}{16}$
• D

  $\frac{7}{32}$

Hence, the correct answer is option: 'C'.