Q27 / 180 · KCET 2018 · Chemistry
For the redox reaction
\( \mathrm{xMnO}_{4}^{-}+\mathrm{yH}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+\mathrm{zH}^{+} \rightarrow \mathrm{mMn}^{2+}+\mathrm{nCO}_{2}+\mathrm{pH}_{2} \mathrm{O} \)
The values of \( \mathrm{x}, \mathrm{y}, \mathrm{m} \) and \( \mathrm{n} \) are
\( \mathrm{xMnO}_{4}^{-}+\mathrm{yH}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+\mathrm{zH}^{+} \rightarrow \mathrm{mMn}^{2+}+\mathrm{nCO}_{2}+\mathrm{pH}_{2} \mathrm{O} \)
The values of \( \mathrm{x}, \mathrm{y}, \mathrm{m} \) and \( \mathrm{n} \) are
- A\( 10,2,5,2 \)
- Correct answerB\( 2,5,2,10 \)
- C\( 6,4,2,5 \)
- D\( 3,5,2,10 \)
Solution
The balance chemical equation is,
\( 2 \mathrm{MnO}_{4}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+6 \mathrm{H}^{+} \rightarrow 2 \mathrm{Mn}^{2+}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O} \)
Therefore, the value of stoichiometric constants is,
\( x=2 ; y=5 ; m=2 \) and \( n=10 \)
\( 2 \mathrm{MnO}_{4}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+6 \mathrm{H}^{+} \rightarrow 2 \mathrm{Mn}^{2+}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O} \)
Therefore, the value of stoichiometric constants is,
\( x=2 ; y=5 ; m=2 \) and \( n=10 \)
Hence, the correct answer is option: 'B'.