Q60 / 160 · JIPMER 2011 · Chemistry

For the reaction, $\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ at 373 K and 1 atm pressure

  • A
    $\Delta H=0$
  • B
    $\Delta E=0$
  • Correct answer
    C
    $\Delta H=T \Delta S$
  • D
    $\Delta H=\Delta E$

Solution

$\Delta G=\Delta H-T \cdot \Delta S$ For the reaction, $\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_2 \mathrm{O}(\mathrm{g})$ $\Delta G=0$ (at equilibrium) $\therefore \quad \Delta H=T \cdot \Delta S$

Hence, the correct answer is option: 'C'.

Relevant Questions