Q13 / 160 · TS EAMCET 2021 (06 Aug Shift 1) · Chemistry

For the reaction, $\mathrm{H}_2(g)+\mathrm{I}_2(g) \rightleftharpoons 2 \mathrm{HI}(g)$

  • Correct answer
    A
    $K_p=K_C \neq 0$
  • B
    $K_p>K_C$
  • C
    $K_p < K_c$
  • D
    $K_p=K_C=0$

Solution

$\mathrm{H}_2(g)+\mathrm{I}_2(g) \rightleftharpoons 2 \mathrm{HI}(g)$ For $K_p$ we use partial pressure of each gaseous species and $K_p$ expression is written as, $K_p=\frac{[\mathrm{HI}]^2}{\left[\mathrm{H}_2\right]\left[\mathrm{I}_2\right]}$ Relationship between $K_p$ and $K_c$ $K_p=K_C(R T)^{\Delta n}$ $\Delta n=$ Moles of gaseous products - moles of gaseous $\begin{aligned} & \Delta n=2-2=0 \Rightarrow K_p=K_C(R T)^0 \\ & K_p=K_C \Rightarrow K_C=\frac{[\mathrm{HI}]^2}{\left[\mathrm{H}_2\right]\left[\mathrm{I}_2\right]} \\ \therefore \quad & K_p=K_C \neq 0 \end{aligned}$

Hence, the correct answer is option: 'A'.

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