Q173 / 270 · NDA 2012 (Phase 1) · Mathematics
For the next Two (2) questions that follow:
The equation formed by multiplying each root of $a x^2+b x+c=0$ by 2 is $x^2+36 x+24=0$.
The equation formed by multiplying each root of $a x^2+b x$ $+c=0$ by 2 is $x^2+36 x+24=0$.
What is $b: c$ equal to?
- Correct answerA$3: 1$
- B$1: 2$
- C$1: 3$
- D$3: 2$
Solution
Let $\alpha, \beta$ be roots of equation
$\begin{aligned}
a x^2+b x+c & =0 \\
\therefore \quad \alpha+\beta & =-b / a \\
\alpha \beta & =c / a
\end{aligned}$
So, $2 \alpha$ and $2 \beta$ we roots of equation
$\begin{aligned}
x^2+36 x+24 & =0 \\
2 \alpha+2 \beta & =-36 \\
\alpha+\beta & =-18 \\
\Rightarrow \quad \frac{-b}{a} & =-18 \Rightarrow b=18 a \\
\Rightarrow \quad(2 \alpha)+(2 \beta) & =24 \\
\alpha \beta & =6 \\
\frac{c}{a} & =6 \Rightarrow c=6 a \\
\therefore b: c=3: & 1 .
\end{aligned}$
Hence, the correct answer is option: 'A'.