Q109 / 160 · AP EAMCET 2021 (24 Aug Shift 2) · Mathematics
For the function $f(x)=x^3-6 x^2-12 x-3$, $x=2$ is a
- Apoint of maxima
- Bpoint of minima
- Correct answerCpoint of inflection
- Dnot a critical point
Solution
We have,
$\begin{aligned} f(x) & =x^3-6 x^2-12 x-3 \\ f^{\prime}(x) & =3 x^2-12 x-12 \\ f^{\prime \prime}(x) & =6 x-12 \Rightarrow f^{\prime \prime}(2)=12-12=0\end{aligned}$
Here, $f^{\prime \prime}(x)=0$ at $x=2$
$\therefore x=2$ is a point of inflection.
Hence, the correct answer is option: 'C'.