For the following electrochemical cell at $\text{289 K,}$
$\text{Pt}\left(\text{s}\right)\left|{\text{H}}_2\left(\text{g},1\text{ bar}\right) \right|{\text{H}}^{+}\left(\text{aq},1\text{M}\right)\left|\right|{\text{ M}}^{4+}\left(\text{aq}.\right){\text{, M}}^{\text{2+}}(\text{aq}.)|\text{ Pt}(\text{s})$
${\mathrm{E}}_{\mathrm{c}\mathrm{e}\mathrm{l}\mathrm{l}}=0.092\mathrm{ }\mathrm{V}$ when $\frac{\left[{\mathrm{M}}^{2+}\left(\mathrm{a}\mathrm{q}.\right)\right]}{\left[{\mathrm{M}}^{4+}\left(\mathrm{a}\mathrm{q}.\right)\right]}={10}^{\mathrm{x}}$
Given: ${\mathrm{E}}_{{\mathrm{M}}^{4+}/{\mathrm{M}}^{2+}}^0=0.151\mathrm{ }\mathrm{V}\mathrm{ };2.303\frac{\mathrm{R}\mathrm{T}}{\mathrm{F}}=0.059$
The value of $\text{x}$ is -

• A

  -2
• B

  -1
• C

  1
• Correct answer
  D

  2

Hence, the correct answer is option: 'D'.