Q29 / 90 · JEE Main 2021 (27 Jul Shift 2) · Chemistry

For the first order reaction A→2 B,1 mole of reactant A gives 0.2 moles of B after 100 minutes. The half life of the reaction is ...... min. (Round off to the nearest integer).

[Use :ln2=0.69,ln10=2.3

Properties of logarithms :lnxy=ylnx

lnxy=lnx-lny

(Round off to the nearest integer)

Correct answer: 655

Solution

                                 A  ⟶  2 Bt=0                         1t=100min           1-x        2x

2x=0.2 ⇒x=0.1[At]=1-x=0.9   

Now, t=t1/2ln2×A0At

100=t1/2ln2×ln10.9⇒t1/2=655 min

(taking ln 3=1.11)

Hence, the correct answer is 655.

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