Q131 / 180 · KCET 2009 · Physics
For the constructive interference the path difference between the two interfering waves must be equal to
- A$(2 \mathrm{n}+1) \lambda$
- B$2 \mathrm{n} \pi$
- Correct answerC$\mathrm{n} \lambda$
- D$(2 \mathrm{n}+1) \frac{\lambda}{2}$
Solution
Phase difference,
$\Delta \phi=\frac{2 \pi}{\lambda} \Delta \mathrm{x}$
In a constructive interference,
$\begin{array}{cc}
\Delta \phi=2 \mathrm{n} \pi & \text { where } \mathrm{n}=0,1,2,3, \ldots \\
\therefore \quad 2 \mathrm{n} \pi=\frac{2 \pi}{\lambda} \Delta \mathrm{x} \\
\text { or } \quad & \Delta \mathrm{x}=\mathrm{n} \lambda
\end{array}$
Hence, the correct answer is option: 'C'.