Q44 / 180 · KCET 2024 · Chemistry
For the coagulations of positively charged hydrated ferric - oxide sol, the flocculating power of the ions is in the order:
- A$\mathrm{PO}_4^{3-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{Cl}^{-}\gt\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}$
- B$\mathrm{Cl}^{-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{PO}_4^{3-}\gt\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}$
- C$\mathrm{SO}_4^{2-}=\mathrm{Cl}^{-}=\mathrm{PO}_4^{3-}=\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}$
- Correct answerD$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\gt\mathrm{PO}_4^{3-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{Cl}^{-}$
Solution
Generally, greater the valence of the flocculating ion added, the greater is its power to cause precipitation. This is called as Hardy-Schulze rule.
So according to Hardy-Schulze rule the flocculating power of the ions is in the order $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\gt\mathrm{PO}_4^{3-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{Cl}^{-}$
Hence, the correct answer is option: 'D'.