Q99 / 150 · MHT CET 2011 · Mathematics

For the circuit show below, the Boolean polynomial is Figure

  • A
    $(\sim p \vee q) \vee(p \vee \sim q)$
  • B
    $(\sim p \wedge q) \wedge(p \wedge q)$
  • C
    $(\sim p \wedge \sim q) \wedge(q \wedge p)$
  • Correct answer
    D
    $(\sim p \wedge q) \vee(p \wedge \sim q)$

Solution

Since, $\sim p$ and $q$ both switch also are in series $$ \Rightarrow \quad(\sim p \wedge q) $$ and $p$ and $\sim q$ both switch also are in series $$ \Rightarrow \quad(p \wedge \sim q) $$ Both Eqs. (i) and (ii) are parallel switch $$ \Rightarrow \quad(\sim p \wedge q) \vee(p \wedge \sim q) $$

Hence, the correct answer is option: 'D'.

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