Q1 / 30 · NTA Abhyas (NEET) 2020 · Physics · Electromagnetic Waves

For plane electromagnetic waves propagating in the z-direction, which one of the following combinations gives the correct possible direction for E→ and B→ field respectively?

  • A
    i^+2j^ and 2i^-j
  • Correct answer
    B
    -2i^-3j^ and 3i^-2j^
  • C
    2i^+3j^ and i^+2j^
  • D
    3i^+4j^ and 4i^-3j^

Solution

The direction of propagation of electromagnetic wave is along E→×B→

Also E→·B→=0

When E→ is along -2 i^-3 j^

And B→ is along 3 i^-2 j^

Then E→×B→=-2i^-3j^×3i^-2j^

=4 k^+9 k^

=13 k^ is along +ve direction also E→·B→=0

Hence, the correct answer is option: 'B'.

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