For hydrogen atom electron in $n^{\mathrm{th}}$ Bohr orbit, the ratio of the radius of orbit to its de-Broglie wavelength is

• Correct answer
  A

  $\frac{n}{2\pi }$
• B

  $\frac{n^2}{2\pi }$
• C

  $\frac{1}{2\pi n}$
• D

  $\frac{1}{2\pi n^2}$

Hence, the correct answer is option: 'A'.