Q102 / 160 · TS EAMCET 2025 (03 May Shift 1) · Mathematics
For $a \neq 0$ and $b \neq 0$, if the real valued function $f(x)=\frac{\sqrt[5]{a(625+x)}-5}{\sqrt[4]{625+b x}-5}$ is continuous at $x=0$, then $f(0)=$
- A$\frac{4 b}{5}$
- B$\frac{5 b}{4}$
- C$\frac{5}{4 b}$
- Correct answerD$\frac{4}{5 b}$
Hence, the correct answer is option: 'D'.