Q135 / 200 · NEET 2002 · Physics

For a transistor $\frac{I_C}{I_E}=0.96$, then the current gain for common emitter configuration:

A
12
B
6
C
48
Correct answer
D
24

Solution

For the common emitter configuration, the current transfer ratio is $\begin{aligned} & \alpha=\frac{I_C}{I_B}=0.96 \\ & \therefore \text { Current gain }=\beta=\frac{\alpha}{1-\alpha} \\ & =\frac{0.96}{1-0.96}=24 \end{aligned}$

Hence, the correct answer is option: 'D'.

Relevant Questions

The above figure shows the circuit symbol of a transistor. Select the correct statements given below: (A) The transistor has two segments of2023 (Manipur)Junction Transistors
The collector current in a common base amplifier using - -n transistor is . If of the electrons released by the emitter is accepted by the c2022 (Phase 2)Junction Transistors
For transistor action, which of the following statements is correct?2020 (Phase 1)Junction Transistors
A n - p - n transistor is connected in common emitter configuration in which collector voltage drop across load resistance ( 800 ) connected2020 (Phase 2)Junction Transistors
In the circuit shown in the figure, the input voltage V i is 20 V , V B E = 0 and V C E = 0 . The values of I B , I C and are given by2018Junction Transistors
In a common-emitter transistor amplifier, the audio signal voltage across the collector is 3 V. The resistance of collector is 3 kΩ . If cur2017Junction Transistors