For a transistor α and β are given as α=I_CI_E and β=I_CI_B. Then the correct relation between α and β will be:

Q62 / 90 · JEE Main 2021 (27 Aug Shift 2) · Physics

For a transistor $α$ and $β$ are given as $α = \frac{I_{C}}{I_{E}}$ and $β = \frac{I_{C}}{I_{B}}$ . Then the correct relation between $α$ and $β$ will be:

A
$α = \frac{1 - β}{β}$
B
$α β = 1$
Correct answer
C
$β = \frac{α}{1 - α}$
D
$α = \frac{β}{1 - β}$

Solution

In the case of the transistor the relation between emitter current, base current and, the collector current is, $i_{E} = i_{B} + i_{C}$ , $\Rightarrow \frac{i_{E}}{i_{C}} = \frac{i_{B}}{i_{C}} + 1$ ,

$\Rightarrow \frac{1}{α} = \frac{1}{β} + 1$

$\Rightarrow β = \frac{α}{1 - α}$

Hence, the correct answer is option: 'C'.

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For a transistor α and β are given as α=ICIE and β=ICIB. Then the correct relation between α and β will be:

Solution

Relevant Questions

For a transistor $α$ and $β$ are given as $α = \frac{I_{C}}{I_{E}}$ and $β = \frac{I_{C}}{I_{B}}$ . Then the correct relation between $α$ and $β$ will be: