Q23 / 90 · KVPY 2012 (SB/SX) · Chemistry

For a tetrahedral complex $\left[\mathbf{M C l}_{4}\right]^{2-}$, the spin-only magnetic moment is $3.83 \mathrm{~B}$.M. The element $\mathbf{M}$ is $-$

  • Correct answer
    A
    $\mathrm{Co}$
  • B
    $\mathrm{Cu}$
  • C
    $\mathrm{Mn}$
  • D
    Fe

Solution

$\left[\mathrm{MCl}_{4}\right]^{2-}$ Tetrahedral $=\mathrm{sp}^{3}$ hybridisation $\mathrm{M}^{+2}$ $\because \mu=\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{B} \cdot \mathrm{M} .=3.83$ $\mathrm{n}=3$ Means configuration of $\mathrm{M}^{+2}=3 \mathrm{~d}^{7}$ so, $M=3 d^{7} 4 s^{2}={ }_{27} C o$

Hence, the correct answer is option: 'A'.

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