Q7 / 16 · NTA Abhyas (NEET) 2020 · Physics · Experimental Physics

For a screw gauge least count of the main scale is 1 mm. Find the minimum number of divisions on the circular scale so that it can measure a diameter of 5 μm

  • A
    500
  • B
    100
  • C
    50
  • Correct answer
    D
    200

Solution

Least count of screw gauge =5 μm

L.C=pitchno. of div on circular  scale

5 μm=1 mmN

N=200

Hence, the correct answer is option: 'D'.

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