Q24 / 75 · JEE Main 2020 (05 Sep Shift 2) · Chemistry

For a reaction $X + Y = 2 Z, 1.0 mol$ of $X, 1.5 mol$ of $Y$ and $0.5 mol$ of $Z$ were taken in a $1 L$ vessel and allowed to react. At equilibrium, the concentration of $Z$ was $1.0 {molL}^{- 1}$ . the equilibrium constant of the reaction is $\dots \dots \dots \dots \frac{x}{15} .$ The value of x is $\dots \dots .$

Correct answer: 16

Solution

$x + y = 2 z$

$t = 0 1 mol$ $1.5 mol 0.5 mol$

Since moles of $Z$ are increased at equilibrium therefore reaction goes in forward direction to attain the
equilibrium.

Hence, the correct answer is 16.