Q117 / 150 · MHT CET 2018 · Physics

For a particle performing linear SHM, its average speed over one oscillation is ( $A =$ amplitude of S.H.M., $n =$ frequency of oscillation)

A
$2 A n$
Correct answer
B
$4 A n$
C
$6 A n$
D
$8 A n$

Solution

Distance travelled in one oscillation is 4

A

and time period is T.

∴

average velocity

= \frac{4 A}{T} = 4 A n

Hence, the correct answer is option: 'B'.

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