Q14 / 160 · AP EAMCET 2008 · Chemistry

For a crystal, the angle of diffraction $(2 \theta)$ is $90^{\circ}$ and the second order line has a $d$ value of $2.28 Ã…$. The wavelength (in $Ã…$ ) of X-rays used for Bragg's diffraction is

  • Correct answer
    A
    $1.612$
  • B
    $2.00$
  • C
    $2.28$
  • D
    $4.00$

Solution

Given, angle of diffraction $(2 \theta)=90^{\circ}$ $$ \theta=45^{\circ} $$ Distance between two planes, $d=2.28 Ã…$ $$ n=2 \quad[\because \text { second order diffraction }] $$ Bragg's equation is $$ \begin{aligned} n \lambda & =2 d \sin \theta \\ 2 \times \lambda & =2 \times 2.28 \times \sin 45^{\circ} \\ \lambda & =1.612 \end{aligned} $$

Hence, the correct answer is option: 'A'.

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