Q62 / 90 · JEE Main 2016 (03 Apr) · Physics

For a common emitter configuration, if α and β have their usual meanings, the correct relationship between α and β is:

  • Correct answer
    A
    α=β1+β
  • B
    α  =β21+β2
  • C
    1α=1β-1
  • D
    α=β1-β

Solution

IE=IC+IB 

IEIC=1+IBIC

1∝=1+1β

 1∝=β+1β

∝=β1+β

Hence, the correct answer is option: 'A'.

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