Q22 / 150 · MHT CET 2026 (13 April Shift 1) · Chemistry
For a certain reaction $\Delta H = -50$ kJ and $\Delta S = -100$ J/K find the temperature so that the reaction is spontaneous.
- A$650$ K
- B$600$ K
- C$550$ K
- Correct answerD$450$ K
Solution
For a reaction to be spontaneous, the change in Gibbs free energy must be negative, i.e., $\Delta G < 0$.
Using the Gibbs free energy equation:
$\Delta G = \Delta H - T\Delta S$
Substituting the given values ($\Delta H = -50000$ J and $\Delta S = -100$ J/K):
$-50000 - T(-100) < 0$
$-50000 + 100T < 0$
$100T < 50000$
$T < 500$ K
The reaction is spontaneous at temperatures below $500$ K. Among the given options, only $450$ K satisfies this condition.
Answer: $450$ K
Using the Gibbs free energy equation:
$\Delta G = \Delta H - T\Delta S$
Substituting the given values ($\Delta H = -50000$ J and $\Delta S = -100$ J/K):
$-50000 - T(-100) < 0$
$-50000 + 100T < 0$
$100T < 50000$
$T < 500$ K
The reaction is spontaneous at temperatures below $500$ K. Among the given options, only $450$ K satisfies this condition.
Answer: $450$ K
Hence, the correct answer is option: 'D'.