Five equal capacitors each with capacitance $C$ are connected as shown in figure. Then, the equivalent capacitance between $A$ and $B$ is

• A

  5 C
• B

  $\frac{C}{5}$
• C

  $3 C$
• Correct answer
  D

  $C$

Solution

Consider the given circuit,
The circuit can be redrawn as shown below.
The circuit is a balanced bridge. We can remove the capacitor between $C$ and $D$.
Thus, equivalent capacitance between $A$ and $B$ is $C_{A B}=\frac{C}{2}+\frac{C}{2}=C$

Hence, the correct answer is option: 'D'.