Q126 / 160 · AP EAMCET 2020 (22 Sep Shift 2) · Physics
Find the apparent weight of a metallic block of density $5 \mathrm{~g} \mathrm{~cm}^{-3}$ and dimensions $5 \mathrm{~cm} \times 5 \mathrm{~cm} \times 5 \mathrm{~cm}$, in water.
- A$5 \times 5 \times 5 \times 5 \mathrm{gf}$
- B$4 \times 4 \times 4 \times 4 \mathrm{gf}$
- C$5 \times 4 \times 4 \times 4 \mathrm{gf}$
- Correct answerD$4 \times 5 \times 5 \times 5 \mathrm{gf}$
Solution
Density of metallic block,
$$
\rho=5 \mathrm{~g} \mathrm{~cm}^{-3}
$$
Volume of block,
$$
V=5 \mathrm{~cm} \times 5 \mathrm{~cm} \times 5 \mathrm{~cm}
$$
Upthrust force on the metallic block in water,
$$
\begin{array}{rlr}
F_1 & =m \cdot g & \\
& =\rho_w V \times g & {\left[\rho_w=1 \mathrm{~g} \mathrm{~cm}^{-3}\right]} \\
& =V g=5 \times 5 \times 5 \times g & \\
& =5 \times 5 \times 5 g f &
\end{array}
$$
$\therefore$ Apparent weight $=$ Weight of block - Upthrust force
$$
\begin{aligned}
& =m g-5 \times 5 \times 5 g f \\
& =(m-5 \times 5 \times 5) g f \\
& =(\rho V-5 \times 5 \times 5) g f \\
& =(5 \times 5 \times 5 \times 5-5 \times 5 \times 5) g f \\
& =5 \times 5 \times 5(5-1) g f \\
& =5 \times 5 \times 5 \times 4 g f
\end{aligned}
$$
Hence, the correct answer is option: 'D'.