Q14 / 150 · MHT CET 2025 (20 Apr Shift 2) · Chemistry

Find out number of carbon atoms present in 0.35 mole of glucose.

  • A
    $3.011 \times 10^{24}$
  • B
    $6.022 \times 10^{24}$
  • Correct answer
    C
    $1.264 \times 10^{24}$
  • D
    $2.044 \times 10^{24}$

Solution

The chemical formula of glucose is C6H12O6, indicating 6 carbon atoms per molecule.

For 0.35 mole of glucose, the number of molecules is $0.35 \times 6.022 \times 10^{23} = 2.1077 \times 10^{23}$.

The total carbon atoms are then $2.1077 \times 10^{23} \times 6 = 1.26462 \times 10^{24}$, matching option C.

Hence, the correct answer is option: 'C'.

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