Q96 / 180 · KCET 2019 · Mathematics
\( f: R \rightarrow R \) and \( g:[0, \infty) \rightarrow R \) is defined by \( f(x)=x^{2} \) and \( g(x)=\sqrt{x} \). Which one of the following is
not true?
not true?
- Correct answerAfo \( g(-4)=4 \)
- Bg of \( (-2)=2 \)
- C\( g \circ f(4)=4 \)
- Dfo \( g(2)=2 \)
Solution
(A)
\( f(x)=x^{2} g(x)=\sqrt{x} \)
fo \( g(-4)=f[g(-4)] \) is not defined
\( f(x)=x^{2} g(x)=\sqrt{x} \)
fo \( g(-4)=f[g(-4)] \) is not defined
Hence, the correct answer is option: 'A'.