Experimentally it was found that a metal oxide has formula M_0.98O. Metal M, present as M^(2+) and M^(3+) in its oxide. Fraction of the metal which…

Question

Experimentally it was found that a metal oxide has formula

M_{0.98} O .

Metal M, present as

M^{2 +}

and

M^{3 +}

in its oxide. Fraction of the metal which exists as

M^{3 +}

would be nearly
[Report your answer by rounding it upto nearset whole number]

MARKS Content Team · Accepted Answer

Correct answer: 4. For a one mole of the oxide Moles of M=0.98, Moles of O^(2-)=1 Let moles of M^(3+)=x Moles of M^(2+)=0.98-x on balancing charge 0.98-x×2+3x-2=0 x=0.04 % of M^(3+)=0.04/0.98×100=4.08%≈4%

Experimentally it was found that a metal oxide has formula $M_{0.98} O .$ Metal M, present as $M^{2 +}$ and $M^{3 +}$ in its oxide. Fraction of the metal which exists as $M^{3 +}$ would be nearly
[Report your answer by rounding it upto nearset whole number]

Solution

More Some Basic Concepts of Chemistry Questions

Experimentally it was found that a metal oxide has formula M0.98O. Metal M, present as M2+ and M3+ in its oxide. Fraction of the metal which exists as M3+ would be nearly [Report your answer by rounding it upto nearset whole number]

Solution

More Some Basic Concepts of Chemistry Questions

Experimentally it was found that a metal oxide has formula $M_{0.98} O .$ Metal M, present as $M^{2 +}$ and $M^{3 +}$ in its oxide. Fraction of the metal which exists as $M^{3 +}$ would be nearly
[Report your answer by rounding it upto nearset whole number]